Two adults and four children pay \(\$48\) to get into the fair. A child’s ticket is \(\$6\) less than an adult’s ticket. What is the cost of an adult’s ticket?
Explanation
Let x = the price of an adult’s ticket and \(4(x-6)\)= the price of a child’s ticket. In the problem, the cost of 2 adults’ tickets and 4 children’s tickets is \(\$ 48\). Write and solve an equation: \(2 x+4(x-6)=\$ 48\)
\(2 x+4 x-\$ 24=\$ 48\)
\(6 x-\$ 24=\$ 48\)
\(6 x=\$ 72\)
\(x=\$ 12\)