The legs of a right triangle ABC have lengths 5 and 12. If the legs of another right triangle PQR have lengths 8 and 6, how much greater is the perimeter of ΔABC as compared to the perimeter of ΔPQR?


The hypotenuse of these triangles can be found using Pythagoras Theorem. For ABC it is 13 and for PQR it is 10. So perimeter of ABC is 30 and that of PQR is 24. Difference is 6.

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