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The average of \(3^{20}, 3^{30}, 3^{40}\)  will be?

Explanation

\(\left(3^{20}+3^{30}+3^{40}\right) / 3=\frac{3^{20}}{3}+\frac{3^{30}}{3}+\frac{3^{40}}{3}=3^{19}+3^{29}+3^{39}\)

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