In the figure below, the pool of water for a fountain has a radius of 6 m. The cement walk that surrounds the pool is 1 m wide. What is the approximate distance, in metres, around the outer edge of the cement walkway?


\(C=\pi d\)
\(\pi = 3.14\)
\(d = 14\) (from the diagram)
Therefore, the distance (or circumference) around the cement walkway is 3.14 multiplied by 14, which equals 43.96 m. This figure is rounded to 44 m.

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