If the area of one shaded square is \(4 {m^2}\) , what is will be the length of the diagonal AB shown in the figure?

\(2 \sqrt{2} \mathrm{~m}\)


Since the area of any square is 4, length of any side of the square is 2. Now if take right triangle ACB with base = height = 2, then length \(A B=\sqrt{2^{2}+2^{2}}=2 \sqrt{2}\)

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