How many bricks each of size \(25 \mathrm{~cm} \times 13.5 \mathrm{~cm} \times 6 \mathrm{~cm}\), will be required to build a wall 8 m long, 5.4 m high and 33 cm thick?

A. 7040

Explanation

\(\text { We know that volume of cuboid }=\text { length } \times \text { breadth } \times \text { height }\)

So,

\(\text { Volume of the brick }=25 \times 13.5 \times 6=2025 \mathrm{~cm}^3\)

\(\text { Volume of the wall }=800 \times 540 \times 33=14256000 \mathrm{~cm}^3\)

\(\text { Therefore, total number of bricks required }=\frac{V \text { olume of the wall }}{V \text { olume of each brick }}\)

\(\begin{aligned} &=1425000 / 2025 \\ &=7040 \text { bricks } \end{aligned}\)

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