How many bricks each of size $$25 \mathrm{~cm} \times 13.5 \mathrm{~cm} \times 6 \mathrm{~cm}$$, will be required to build a wall 8 m long, 5.4 m high and 33 cm thick?

A. 7040

Explanation

$$\text { We know that volume of cuboid }=\text { length } \times \text { breadth } \times \text { height }$$

So,

$$\text { Volume of the brick }=25 \times 13.5 \times 6=2025 \mathrm{~cm}^3$$

$$\text { Volume of the wall }=800 \times 540 \times 33=14256000 \mathrm{~cm}^3$$

$$\text { Therefore, total number of bricks required }=\frac{V \text { olume of the wall }}{V \text { olume of each brick }}$$

\begin{aligned} &=1425000 / 2025 \\ &=7040 \text { bricks } \end{aligned}

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