Consider the following information: 

When a force acts on an object to cause a displacement (d) of the object, it is said that work (W) was done on the object. 

Power is the rate at which work is done. It is the work/time ratio. Mathematically, it is computed using the following equation:

Power (P) = work (W) / time (t)

→ P = [ force (F) x displacement (dx) ] / t

→ P = F x velocity (v)

→ P = Fv

When a force acts on an object to cause a displacement (d) of the object, it is said that work (W) was done on the object.
Power is the rate at which work is done. It is the work/time ratio. Mathematically, it is computed using the following equation:
Power (P) = work (W) / time (t)
→ P = [ force (F) x displacement (dx) ] / t
→ P = F x velocity (v)
→ P = Fv
A man does a push-up by applying a force, which results in 0.50 J of work. If it takes 2 seconds to do the push-up, what is his power?

B. 0.25 W

Explanation

P = W/t = (0.50 J) / (2.0 s) = 0.25 W. Choice B is correct.

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