Explanation
There are a number of ways to solve this problem. One way is to find the areas of the outside triangle pieces. Each has a base of 8 cm and a height of 8 cm.
A = \(\frac{1}{2}\)bh
A = \(\frac{1}{2}\)(8)(8)
A = 4(8)
A = 32
Since there are 4 triangles left, the total area is \(4 \times 32\), or 128, square centimeters.